Prerequisites: lines, exponents, logs, trig

Exponent rules and exponential functions

Exponent rules: multiplying adds exponents, and a power of a power multiplies them.

aman=am+n,(am)n=amn,a−n=1an,a1n=an\begin{gathered} a^m a^n=a^{m+n},\quad (a^m)^n=a^{mn}, \\[4pt] a^{-n}=\frac{1}{a^n},\quad a^{\frac{1}{n}}=\sqrt[n]{a} \end{gathered}

Two rules do most of the work: multiplying adds exponents, and a power of a power multiplies them.

aman=am+n,(am)n=amna^m a^n=a^{m+n},\qquad (a^m)^n=a^{mn}

Exponents extend beyond positive integers: a0=1a^0=1 (a≠0a\neq 0), a−n=1ana^{-n}=\dfrac{1}{a^n}, and a1/na^{1/n} is the nn-th root. For example, 81/3=28^{1/3}=2 and 2−3=182^{-3}=\dfrac{1}{8}.

In calculus you use these rules directly when differentiating or integrating exe^x, and when rewriting axa^x as exln⁡ae^{x\ln a}.

Examples

  1. 01Evaluate:813\displaystyle 8^{\frac{1}{3}}AnswerHide
    Answer2\displaystyle 2

    Steps

    1. 813\displaystyle 8^{\frac{1}{3}}=(23)13\displaystyle = (2^{3})^{\frac{1}{3}}=2\displaystyle = 2
  2. 02What is the value?a0(a≠0)\displaystyle a^{0} \quad (a \neq 0)AnswerHide
    Answer1\displaystyle 1

    Steps

    1. a3÷a3\displaystyle a^{3} \div a^{3}=1\displaystyle = 1
    2. Write the same thing two ways
    3. a3÷a3\displaystyle a^{3} \div a^{3}=a3−3=a0\displaystyle = a^{3-3} = a^{0}
  3. 03Write as a fraction:2−3\displaystyle 2^{-3}AnswerHide
    Answer18\displaystyle \frac{1}{8}

    Steps

    1. 2−3\displaystyle 2^{-3}=123\displaystyle = \frac{1}{2^{3}}=18\displaystyle = \frac{1}{8}
  4. 04What number goes in □?a5÷a2=a□\displaystyle a^{5} \div a^{2} = a^{\square}AnswerHide
    Answer3\displaystyle 3

    Steps

    1. a5÷a2\displaystyle a^{5} \div a^{2}=a5−2\displaystyle = a^{5-2}=a3\displaystyle = a^{3}
  5. 05Evaluate:(23)3\displaystyle (2^{3})^{3}AnswerHide
    Answer29\displaystyle 2^{9}

    Steps

    1. (23)3\displaystyle (2^{3})^{3}=23×3\displaystyle = 2^{3 \times 3}=29\displaystyle = 2^{9}
  6. 06Write as a fraction:5−2\displaystyle 5^{-2}AnswerHide
    Answer125\displaystyle \frac{1}{25}

    Steps

    1. 5−2\displaystyle 5^{-2}=152\displaystyle = \frac{1}{5^{2}}=125\displaystyle = \frac{1}{25}

FAQ

Why is a0a^0 equal to 1?
For the rule aman=am+na^m a^n=a^{m+n} to hold with n=0n=0 we need ama0=ama^m a^0=a^m, so a0=1a^0=1 (for a≠0a\neq 0). The same reasoning fixes a−n=1/ana^{-n}=1/a^n.

Published 2026-09-04 · Updated 2026-10-15