Don't drop the middle term 2ab in (a+b)2=a2+2ab+b2. For example, (x+5)2=x2+10x+25.
The coefficients of the cube are 1, 3, 3, 1. When b is negative, the signs alternate +, −, +, −.
(x−1)3=x3−3x2+3x−1
With f(x)=x2, f(x+h)=(x+h)2=x2+2xh+h2. Then hf(x+h)−f(x)=2x+h, and letting h→0 gives f′(x)=2x.
Examples
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01Expand:(x+3)3AnswerHide
Answerx3+9x2+27x+27
Steps
- (x+3)3=(x+3)2(x+3)=(x2+6x+9)(x+3)
- Multiply term by term, then collect like terms
- =x3+3x2+6x2+18x+9x+27=x3+9x2+27x+27
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02Which expression expands to this?x2+4x+4AnswerHide
Answer(x+2)2
Steps
- x2+2⋅2x+22=(x+2)2
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03With f(x)=x2, what goes in □?f(x+h)=x2+□h+h2AnswerHide
Answer2x
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04After expanding, what number goes in □?(x+5)2=x2+□x+25AnswerHide
Answer10
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05Expand:(x−2)2AnswerHide
Answerx2−4x+4
Steps
- (x−2)2=(x−2)(x−2)=x2−2x−2x+4=x2−4x+4
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06Expand:(x−1)3AnswerHide
Answerx3−3x2+3x−1
Steps
- (x−1)3=(x−1)2(x−1)=(x2−2x+1)(x−1)
- Multiply term by term, then collect like terms
- =x3−x2−2x2+2x+x−1=x3−3x2+3x−1
FAQ
Q1Isn't (x+3)2 equal to x2+9?AnswerHide
ANo.
(x+3)2=(x+3)(x+3)=x2+6x+9; the middle term
2⋅3⋅x=6x is included.
Q2How do I get the coefficients of (x+3)3?AnswerHide
APut
a=x and
b=3 into
(a+b)3=a3+3a2b+3ab2+b3:
x3+3⋅3x2+3⋅9x+27=x3+9x2+27x+27.