As with differentiation, constant multiples come outside and sums and differences are integrated term by term. For a polynomial, apply the ∫xndx formula to each term.
∫(6x2−4x+1)dx=2x3−2x2+x+C
One C at the end is enough.
Examples
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01Integrate:∫(3x2−6x+1)dxAnswerHide
Answerx3−3x2+x+C
Steps
- ∫(3x2−6x+1)dx=33x3−26x2+1x+C
- Tidy the coefficients
- 33x3−26x2+1x=x3−3x2+x
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02Integrate∫x2dxAnswerHide
Answer31x3+C
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03Integrate:∫(6x2+6x)dxAnswerHide
Answer2x3+3x2+C
Steps
- ∫(6x2+6x)dx=36x3+26x2+C
- Tidy the coefficients
- 36x3+26x2=2x3+3x2
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04Integrate:∫(9x2−4x+4)dxAnswerHide
Answer3x3−2x2+4x+C
Steps
- ∫(9x2−4x+4)dx=39x3−24x2+4x+C
- Tidy the coefficients
- 39x3−24x2+4x=3x3−2x2+4x
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05Integrate:∫(6x2−4x+4)dxAnswerHide
Answer2x3−2x2+4x+C
Steps
- ∫(6x2−4x+4)dx=36x3−24x2+4x+C
- Tidy the coefficients
- 36x3−24x2+4x=2x3−2x2+4x
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06Integrate:∫(9x2−2x+5)dxAnswerHide
Answer3x3−x2+5x+C
Steps
- ∫(9x2−2x+5)dx=39x3−22x2+5x+C
- Tidy the coefficients
- 39x3−22x2+5x=3x3−x2+5x
FAQ
QDo I add C to every term?
AOne C at the end is enough. The constants from each term are combined into a single C.