Integrals: the basics

Constant multiples, sums and differences (polynomials)

To integrate a polynomial, take constants outside and apply the ∫xn dx\int x^n\,dx formula term by term.

∫kf dx=k∫f dx,∫(f±g) dx=∫f dx±∫g dx\begin{gathered} \int kf\,dx=k\int f\,dx, \\[4pt] \int (f\pm g)\,dx=\int f\,dx\pm\int g\,dx \end{gathered}

As with differentiation, constant multiples come outside and sums and differences are integrated term by term. For a polynomial, apply the ∫xn dx\int x^n\,dx formula to each term.

∫(6x2−4x+1) dx=2x3−2x2+x+C\int (6x^2-4x+1)\,dx=2x^3-2x^2+x+C

One CC at the end is enough.

Examples

  1. 01Integrate:∫(3x2−6x+1) dx\displaystyle \int (3x^2-6x+1)\,dxAnswerHide
    Answerx3−3x2+x+C\displaystyle x^3-3x^2+x+C

    Steps

    1. ∫(3x2−6x+1) dx\displaystyle \int (3x^2-6x+1)\,dx=33x3−62x2+1x+C\displaystyle = \frac{3}{3}x^3 - \frac{6}{2}x^2 + 1x + C
    2. Tidy the coefficients
    3. 33x3−62x2+1x\displaystyle \frac{3}{3}x^3 - \frac{6}{2}x^2 + 1x=x3−3x2+x\displaystyle = x^3-3x^2+x
  2. 02Integrate∫x2 dx\displaystyle \int x^{2} \, dxAnswerHide
    Answer13x3+C\displaystyle \frac{1}{3}x^{3} + C
  3. 03Integrate:∫(6x2+6x) dx\displaystyle \int (6x^2+6x)\,dxAnswerHide
    Answer2x3+3x2+C\displaystyle 2x^3+3x^2+C

    Steps

    1. ∫(6x2+6x) dx\displaystyle \int (6x^2+6x)\,dx=63x3+62x2+C\displaystyle = \frac{6}{3}x^3 + \frac{6}{2}x^2 + C
    2. Tidy the coefficients
    3. 63x3+62x2\displaystyle \frac{6}{3}x^3 + \frac{6}{2}x^2=2x3+3x2\displaystyle = 2x^3+3x^2
  4. 04Integrate:∫(9x2−4x+4) dx\displaystyle \int (9x^2-4x+4)\,dxAnswerHide
    Answer3x3−2x2+4x+C\displaystyle 3x^3-2x^2+4x+C

    Steps

    1. ∫(9x2−4x+4) dx\displaystyle \int (9x^2-4x+4)\,dx=93x3−42x2+4x+C\displaystyle = \frac{9}{3}x^3 - \frac{4}{2}x^2 + 4x + C
    2. Tidy the coefficients
    3. 93x3−42x2+4x\displaystyle \frac{9}{3}x^3 - \frac{4}{2}x^2 + 4x=3x3−2x2+4x\displaystyle = 3x^3-2x^2+4x
  5. 05Integrate:∫(6x2−4x+4) dx\displaystyle \int (6x^2-4x+4)\,dxAnswerHide
    Answer2x3−2x2+4x+C\displaystyle 2x^3-2x^2+4x+C

    Steps

    1. ∫(6x2−4x+4) dx\displaystyle \int (6x^2-4x+4)\,dx=63x3−42x2+4x+C\displaystyle = \frac{6}{3}x^3 - \frac{4}{2}x^2 + 4x + C
    2. Tidy the coefficients
    3. 63x3−42x2+4x\displaystyle \frac{6}{3}x^3 - \frac{4}{2}x^2 + 4x=2x3−2x2+4x\displaystyle = 2x^3-2x^2+4x
  6. 06Integrate:∫(9x2−2x+5) dx\displaystyle \int (9x^2-2x+5)\,dxAnswerHide
    Answer3x3−x2+5x+C\displaystyle 3x^3-x^2+5x+C

    Steps

    1. ∫(9x2−2x+5) dx\displaystyle \int (9x^2-2x+5)\,dx=93x3−22x2+5x+C\displaystyle = \frac{9}{3}x^3 - \frac{2}{2}x^2 + 5x + C
    2. Tidy the coefficients
    3. 93x3−22x2+5x\displaystyle \frac{9}{3}x^3 - \frac{2}{2}x^2 + 5x=3x3−x2+5x\displaystyle = 3x^3-x^2+5x

FAQ

Do I add C to every term?
One C at the end is enough. The constants from each term are combined into a single C.

Published 2026-09-03 · Updated 2026-10-14