Integrals: the basics

Definite integrals: F(b) − F(a)

A definite integral ∫abf(x) dx\int_a^b f(x)\,dx is computed as F(b)−F(a)F(b)-F(a) using an antiderivative F(x)F(x).

∫abf(x) dx=[F(x)]ab=F(b)−F(a)\begin{gathered} \int_a^b f(x)\,dx \\[4pt] =\Big[F(x)\Big]_a^b \\[4pt] =F(b)-F(a) \end{gathered}

For a definite integral, find an antiderivative F(x)F(x), then subtract its value at the lower limit aa from its value at the upper limit bb.

∫abf(x) dx=F(b)−F(a)\int_a^b f(x)\,dx=F(b)-F(a)

CC cancels in the subtraction, so it is not needed. Sign mistakes are common, so write F(b)F(b) and F(a)F(a) separately before subtracting.

xyy = f(x)abF(b) − F(a)
The definite integral is the area between the curve and the x-axis from a to b.Drag the dot

Examples

  1. 01What is this definite integral?∫122x dx\displaystyle \int_{1}^{2} 2x \, dxAnswerHide
    Answer3\displaystyle 3

    Steps

    1. ∫122x dx\displaystyle \int_{1}^{2} 2x \, dx=[x2]12\displaystyle = \left[x^{2}\right]_{1}^{2}=22−12\displaystyle = 2^{2} - 1^{2}=3\displaystyle = 3
  2. 02What is this definite integral?∫−113x2 dx\displaystyle \int_{-1}^{1} 3x^2 \, dxAnswerHide
    Answer2\displaystyle 2

    Steps

    1. ∫−113x2 dx\displaystyle \int_{-1}^{1} 3x^2 \, dx=[x3]−11\displaystyle = \left[x^{3}\right]_{-1}^{1}=13−(−1)3\displaystyle = 1^{3} - (-1)^{3}=2\displaystyle = 2
  3. 03What is this definite integral?∫−132x dx\displaystyle \int_{-1}^{3} 2x \, dxAnswerHide
    Answer8\displaystyle 8

    Steps

    1. ∫−132x dx\displaystyle \int_{-1}^{3} 2x \, dx=[x2]−13\displaystyle = \left[x^{2}\right]_{-1}^{3}=32−(−1)2\displaystyle = 3^{2} - (-1)^{2}=8\displaystyle = 8
  4. 04What is this definite integral?∫−3−12x dx\displaystyle \int_{-3}^{-1} 2x \, dxAnswerHide
    Answer−8\displaystyle -8

    Steps

    1. ∫−3−12x dx\displaystyle \int_{-3}^{-1} 2x \, dx=[x2]−3−1\displaystyle = \left[x^{2}\right]_{-3}^{-1}=(−1)2−(−3)2\displaystyle = (-1)^{2} - (-3)^{2}=−8\displaystyle = -8
  5. 05What is this definite integral?∫013x2 dx\displaystyle \int_{0}^{1} 3x^2 \, dxAnswerHide
    Answer1\displaystyle 1

    Steps

    1. ∫013x2 dx\displaystyle \int_{0}^{1} 3x^2 \, dx=[x3]01\displaystyle = \left[x^{3}\right]_{0}^{1}=13−03\displaystyle = 1^{3} - 0^{3}=1\displaystyle = 1
  6. 06What is this definite integral?∫−103x2 dx\displaystyle \int_{-1}^{0} 3x^2 \, dxAnswerHide
    Answer1\displaystyle 1

    Steps

    1. ∫−103x2 dx\displaystyle \int_{-1}^{0} 3x^2 \, dx=[x3]−10\displaystyle = \left[x^{3}\right]_{-1}^{0}=03−(−1)3\displaystyle = 0^{3} - (-1)^{3}=1\displaystyle = 1

FAQ

What if I swap the upper and lower limits?
The sign flips: ∫baf(x) dx=−∫abf(x) dx\int_b^a f(x)\,dx=-\int_a^b f(x)\,dx.

Published 2026-09-03 · Updated 2026-09-05