Integrals: the basics

Area between two curves

The area between two curves is the integral, from intersection to intersection, of the upper function minus the lower one.

S=ab{f(x)g(x)}dx(f(x)g(x))\begin{gathered} S \\[4pt] =\int_a^b \{f(x)-g(x)\}\,dx\quad(f(x)\ge g(x)) \end{gathered}

The area between two graphs is the integral of the upper function minus the lower one.

S=ab{f(x)g(x)}dx(f(x)g(x))\begin{gathered} S=\int_a^b\{f(x)-g(x)\}\,dx \\[4pt] (f(x)\ge g(x)) \end{gathered}

Check which is on top on each interval, and use the xx-coordinates of the intersections as the limits. If the curves swap places, split the interval.

xyy = x + 2y = x²ab
Integrate the upper function minus the lower one, between the intersections.Drag the dot

Examples

  1. 01For 0<x<3, which expression gives the area between these two curves?y=3x,y=x2\displaystyle y=3x,\quad y=x^2AnswerHide
    Answer03(3xx2)dx\displaystyle \int_{0}^{3} (3x-x^2)\,dx
  2. 02The area enclosed by y=9y=9 and y=x2y=x^2. What goes in □?33()dx\displaystyle \int_{-3}^{3} (\square)\,dxAnswerHide
    Answer9x2\displaystyle 9-x^2
  3. 03Which expression gives the area between these two curves?y=4,y=x2\displaystyle y=4,\quad y=x^2AnswerHide
    Answer22(4x2)dx\displaystyle \int_{-2}^{2} (4-x^2)\,dx
  4. 04The area enclosed by y=1y=1 and y=x2y=x^2. What goes in □?11()dx\displaystyle \int_{-1}^{1} (\square)\,dxAnswerHide
    Answer1x2\displaystyle 1-x^2
  5. 05The curves meet at x=0 and x=4, and y=4x is on top between them. What is the enclosed area?y=4x,y=x2\displaystyle y=4x,\quad y=x^2AnswerHide
    Answer323\displaystyle \frac{32}{3}
  6. 06Which expression gives the area between these two curves?y=16,y=x2\displaystyle y=16,\quad y=x^2AnswerHide
    Answer44(16x2)dx\displaystyle \int_{-4}^{4} (16-x^2)\,dx

FAQ

Q1Which function do I subtract?Show answerHide
A
Subtract the lower function from the upper one. If they swap places inside the interval, split at the intersection and integrate each part separately.

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Published 2026-09-03 · Updated 2026-09-05