Apply the quotient rule to tanx=cosxsinx. The numerator becomes cos2x+sin2x=1.
(tanx)′=cos2xcosx⋅cosx−sinx⋅(−sinx)=cos2x1
You can memorize the result, but derive it by hand once so it sticks.
Examples
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01Differentiate:tanxAnswerHide
Answercos2x1
Steps
- Quotient rule on tanx=cosxsinx: the numerator collapses to cos2x+sin2x
- cos2xcos2x+sin2x=cos2x1
- The denominator is the original cos2x; not sin2x
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02What is the value?cos2x+sin2xAnswerHide
Steps
- This holds for every x
- sin2x+cos2x=1
- At x=0 for instance, sin0=0 and cos0=1, and 0+1=1
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03What is the value at x=0?(tanx)′=cos2x1AnswerHide
Steps
- Put in cos0=1
- 121=1
- Slope 1; the graph of tanx leaves the origin at 45 degrees
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04What goes in □?tanx=□sinxAnswerHide
Answercosx
Steps
- This is what tan means
- tanx=cosxsinx
- At x=4π, for instance, sin and cos are equal so the quotient is 1; matching tan4π=1
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05DifferentiatedxdtanxAnswerHide
Answercos2x1
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06Expand:cosxcosx−sinx(−sinx)AnswerHide
Answercos2x+sin2x
FAQ
QHow do you derive (tanx)′?
AApply the quotient rule to
tanx=cosxsinx. The numerator becomes
cos2x+sin2x=1, giving
cos2x1.