A function with f(−x)=f(x) is even, and one with f(−x)=−f(x) is odd. x2, x4 and constants are even; x, x3 and x5 are odd.
∫−aaxevendx=2∫0axevendx,∫−aaxodddx=0
The graph of an even function is symmetric about the y-axis, so the two halves have equal area; the graph of an odd function is symmetric about the origin, so the two halves cancel. For example, ∫−11x4dx=2∫01x4dx=52.
Examples
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01Which one is an odd function?A2Bx2Cx5Dx2+1AnswerHide
Answerx5
Steps
- (−x)5=−x5
- An even power keeps its sign
- (−x)2=x2
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02If f(x) is odd, what goes in □?∫−aaf(x)dx=□AnswerHide
Steps
- ∫−10x3dx=−41∫01x3dx=41
- Adding them cancels
- ∫−11x3dx=0
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03What is f(-x)?f(x)=x2AnswerHide
Answerx2
Steps
- (−x)2=(−1)2x2=x2
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04x4 is an even function. What is the value of this definite integral?∫−11x4dxAnswerHide
Answer52
Steps
- ∫01x4dx=51
- Even, so twice one side
- ∫−11x4dx=2⋅51=52
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05What is the value of this definite integral?∫−33x5dxAnswerHide
Steps
- ∫−30x5dx=−2243∫03x5dx=2243
- Adding them cancels
- ∫−33x5dx=0
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06What is f(-x)?f(x)=x5AnswerHide
Answer−x5
Steps
- (−x)5=(−1)5x5=−x5
FAQ
Q1What if the function is neither even nor odd, like x5+5?AnswerHide
ASplit it term by term. In
∫−22(x5+5)dx, the odd part
x5 gives
0, and the constant
5 is even, so the result is
2∫025dx=20.
Q2Does this work if the interval is not from −a to a?AnswerHide
ANo. It holds only on an interval
[−a, a] that is symmetric about
0.